Base | Representation |
---|---|
bin | 10100100010100110101… |
… | …001101100010011101011 |
3 | 11222221110000100202101212 |
4 | 110202212221230103223 |
5 | 141111321034022311 |
6 | 3000242132503335 |
7 | 203660256256361 |
oct | 24424651542353 |
9 | 4887400322355 |
10 | 1411545220331 |
11 | 4a46a65291a4 |
12 | 1a969777ab4b |
13 | a315378a2ac |
14 | 4c467a83631 |
15 | 26ab69eac8b |
hex | 148a6a6c4eb |
1411545220331 has 2 divisors, whose sum is σ = 1411545220332. Its totient is φ = 1411545220330.
The previous prime is 1411545220321. The next prime is 1411545220339. The reversal of 1411545220331 is 1330225451141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1411545220331 - 238 = 1136667313387 is a prime.
It is a super-4 number, since 4×14115452203314 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1411545220339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705772610165 + 705772610166.
It is an arithmetic number, because the mean of its divisors is an integer number (705772610166).
Almost surely, 21411545220331 is an apocalyptic number.
1411545220331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411545220331 is an equidigital number, since it uses as much as digits as its factorization.
1411545220331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
The spelling of 1411545220331 in words is "one trillion, four hundred eleven billion, five hundred forty-five million, two hundred twenty thousand, three hundred thirty-one".
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