Base | Representation |
---|---|
bin | 1000001101110101110… |
… | …1111000100011000011 |
3 | 111111100022012012100111 |
4 | 2003131131320203003 |
5 | 4303041031131003 |
6 | 144502343532151 |
7 | 13124640616063 |
oct | 2033535704303 |
9 | 444308165314 |
10 | 141154552003 |
11 | 54955079153 |
12 | 2343445a057 |
13 | 10406b32c6a |
14 | 6b90acb3a3 |
15 | 3a12280e6d |
hex | 20dd7788c3 |
141154552003 has 2 divisors, whose sum is σ = 141154552004. Its totient is φ = 141154552002.
The previous prime is 141154552001. The next prime is 141154552013. The reversal of 141154552003 is 300255451141.
141154552003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141154552003 - 21 = 141154552001 is a prime.
Together with 141154552001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (141154552001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70577276001 + 70577276002.
It is an arithmetic number, because the mean of its divisors is an integer number (70577276002).
Almost surely, 2141154552003 is an apocalyptic number.
141154552003 is a deficient number, since it is larger than the sum of its proper divisors (1).
141154552003 is an equidigital number, since it uses as much as digits as its factorization.
141154552003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 141154552003 in words is "one hundred forty-one billion, one hundred fifty-four million, five hundred fifty-two thousand, three".
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