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141161143340047 is a prime number
BaseRepresentation
bin100000000110001010100011…
…110011100000110000001111
3200111210212120210021210202211
4200012022203303200300033
5122000241010143340142
61220120311202331251
741506361503603165
oct4006124363406017
9614725523253684
10141161143340047
1140a84117396626
12139b9b85359b27
13609c591a8c70c
1426c0343029235
15114bdd2c87917
hex8062a3ce0c0f

141161143340047 has 2 divisors, whose sum is σ = 141161143340048. Its totient is φ = 141161143340046.

The previous prime is 141161143339991. The next prime is 141161143340081. The reversal of 141161143340047 is 740043341161141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141161143340047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141161143339991 and 141161143340009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141161143343047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70580571670023 + 70580571670024.

It is an arithmetic number, because the mean of its divisors is an integer number (70580571670024).

Almost surely, 2141161143340047 is an apocalyptic number.

141161143340047 is a deficient number, since it is larger than the sum of its proper divisors (1).

141161143340047 is an equidigital number, since it uses as much as digits as its factorization.

141161143340047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 40.

The spelling of 141161143340047 in words is "one hundred forty-one trillion, one hundred sixty-one billion, one hundred forty-three million, three hundred forty thousand, forty-seven".