Base | Representation |
---|---|
bin | 100000000110101111101100… |
… | …101101111110101000110001 |
3 | 200111221200111221202200201101 |
4 | 200012233230231332220301 |
5 | 122001414142430111032 |
6 | 1220150504222204401 |
7 | 41512302640130353 |
oct | 4006575455765061 |
9 | 614850457680641 |
10 | 141201021332017 |
11 | 40a9a020491189 |
12 | 13a05854423701 |
13 | 60a327879407a |
14 | 26c22473170d3 |
15 | 114ce68bbdde7 |
hex | 806becb7ea31 |
141201021332017 has 2 divisors, whose sum is σ = 141201021332018. Its totient is φ = 141201021332016.
The previous prime is 141201021332011. The next prime is 141201021332057. The reversal of 141201021332017 is 710233120102141.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 139385437557921 + 1815583774096 = 11806161^2 + 1347436^2 .
It is a cyclic number.
It is not a de Polignac number, because 141201021332017 - 23 = 141201021332009 is a prime.
It is not a weakly prime, because it can be changed into another prime (141201021332011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600510666008 + 70600510666009.
It is an arithmetic number, because the mean of its divisors is an integer number (70600510666009).
Almost surely, 2141201021332017 is an apocalyptic number.
It is an amenable number.
141201021332017 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201021332017 is an equidigital number, since it uses as much as digits as its factorization.
141201021332017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 141201021332017 its reverse (710233120102141), we get a palindrome (851434141434158).
The spelling of 141201021332017 in words is "one hundred forty-one trillion, two hundred one billion, twenty-one million, three hundred thirty-two thousand, seventeen".
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