1412010243331 has 2 divisors, whose sum is σ = 1412010243332. Its totient is φ = 1412010243330.

The previous prime is 1412010243311. The next prime is 1412010243349. The reversal of 1412010243331 is 1333420102141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1412010243331 - 2¹⁵ = 1412010210563 is a prime.

It is a super-2 number, since 2×1412010243331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1412010243296 and 1412010243305.

It is not a weakly prime, because it can be changed into another prime (1412010243311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706005121665 + 706005121666.

It is an arithmetic number, because the mean of its divisors is an integer number (706005121666).

Almost surely, 2^{1412010243331} is an apocalyptic number.

1412010243331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412010243331 is an equidigital number, since it uses as much as digits as its factorization.

1412010243331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1412010243331 its reverse (1333420102141), we get a palindrome (2745430345472).

The spelling of 1412010243331 in words is "one trillion, four hundred twelve billion, ten million, two hundred forty-three thousand, three hundred thirty-one".