Base | Representation |
---|---|
bin | 100000000110101111101101… |
… | …111001111011100011101111 |
3 | 200111221200120100020020120011 |
4 | 200012233231321323203233 |
5 | 122001414213024223401 |
6 | 1220150510213034051 |
7 | 41512303301304106 |
oct | 4006575571734357 |
9 | 614850510206504 |
10 | 141201041242351 |
11 | 40a9a030750102 |
12 | 13a0585b025927 |
13 | 60a327c94572c |
14 | 26c2249c1b03d |
15 | 114ce6a803451 |
hex | 806bede7b8ef |
141201041242351 has 2 divisors, whose sum is σ = 141201041242352. Its totient is φ = 141201041242350.
The previous prime is 141201041242291. The next prime is 141201041242361. The reversal of 141201041242351 is 153242140102141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141201041242351 - 227 = 141200907024623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141201041242361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600520621175 + 70600520621176.
It is an arithmetic number, because the mean of its divisors is an integer number (70600520621176).
Almost surely, 2141201041242351 is an apocalyptic number.
141201041242351 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201041242351 is an equidigital number, since it uses as much as digits as its factorization.
141201041242351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 141201041242351 its reverse (153242140102141), we get a palindrome (294443181344492).
The spelling of 141201041242351 in words is "one hundred forty-one trillion, two hundred one billion, forty-one million, two hundred forty-two thousand, three hundred fifty-one".
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