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1412013001330 = 251071319638319
BaseRepresentation
bin10100100011000010100…
…010001000101001110010
311222222122121120111022001
4110203002202020221302
5141113300312020310
63000400403004214
7204004666323361
oct24430242105162
94888577514261
101412013001330
114a4916589a68
121a97a836966a
13a31c9671399
144c4adc4d7d8
1526ae2aec93a
hex148c2888a72

1412013001330 has 16 divisors (see below), whose sum is σ = 2565376894080. Its totient is φ = 559526646832.

The previous prime is 1412013001327. The next prime is 1412013001361. The reversal of 1412013001330 is 331003102141.

It is a junction number, because it is equal to n+sod(n) for n = 1412013001298 and 1412013001307.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 659818090 + ... + 659820229.

It is an arithmetic number, because the mean of its divisors is an integer number (160336055880).

Almost surely, 21412013001330 is an apocalyptic number.

1412013001330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1412013001330 is a deficient number, since it is larger than the sum of its proper divisors (1153363892750).

1412013001330 is a wasteful number, since it uses less digits than its factorization.

1412013001330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1319638433.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1412013001330 its reverse (331003102141), we get a palindrome (1743016103471).

The spelling of 1412013001330 in words is "one trillion, four hundred twelve billion, thirteen million, one thousand, three hundred thirty".

Divisors: 1 2 5 10 107 214 535 1070 1319638319 2639276638 6598191595 13196383190 141201300133 282402600266 706006500665 1412013001330