Base | Representation |
---|---|
bin | 10100100011000010100… |
… | …010001000101001101111 |
3 | 11222222122121120111021221 |
4 | 110203002202020221233 |
5 | 141113300312020302 |
6 | 3000400403004211 |
7 | 204004666323355 |
oct | 24430242105157 |
9 | 4888577514257 |
10 | 1412013001327 |
11 | 4a4916589a65 |
12 | 1a97a8369667 |
13 | a31c9671396 |
14 | 4c4adc4d7d5 |
15 | 26ae2aec937 |
hex | 148c2888a6f |
1412013001327 has 2 divisors, whose sum is σ = 1412013001328. Its totient is φ = 1412013001326.
The previous prime is 1412013001319. The next prime is 1412013001361. The reversal of 1412013001327 is 7231003102141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1412013001327 - 23 = 1412013001319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412013001367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706006500663 + 706006500664.
It is an arithmetic number, because the mean of its divisors is an integer number (706006500664).
Almost surely, 21412013001327 is an apocalyptic number.
1412013001327 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412013001327 is an equidigital number, since it uses as much as digits as its factorization.
1412013001327 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1412013001327 its reverse (7231003102141), we get a palindrome (8643016103468).
The spelling of 1412013001327 in words is "one trillion, four hundred twelve billion, thirteen million, one thousand, three hundred twenty-seven".
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