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141201331432531 is a prime number
BaseRepresentation
bin100000000110101111111111…
…001100111010110001010011
3200111221201022120021102122121
4200012233333030322301103
5122001420311321320111
61220150555100515111
741512313424005446
oct4006577714726123
9614851276242577
10141201331432531
1140a9a16a5342a7
1213a0592024ba97
1360a32c7aba3b6
1426c227659965d
15114ce86025871
hex806bff33ac53

141201331432531 has 2 divisors, whose sum is σ = 141201331432532. Its totient is φ = 141201331432530.

The previous prime is 141201331432507. The next prime is 141201331432543. The reversal of 141201331432531 is 135234133102141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141201331432531 - 29 = 141201331432019 is a prime.

It is a super-2 number, since 2×1412013314325312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141201331402531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600665716265 + 70600665716266.

It is an arithmetic number, because the mean of its divisors is an integer number (70600665716266).

Almost surely, 2141201331432531 is an apocalyptic number.

141201331432531 is a deficient number, since it is larger than the sum of its proper divisors (1).

141201331432531 is an equidigital number, since it uses as much as digits as its factorization.

141201331432531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 141201331432531 its reverse (135234133102141), we get a palindrome (276435464534672).

The spelling of 141201331432531 in words is "one hundred forty-one trillion, two hundred one billion, three hundred thirty-one million, four hundred thirty-two thousand, five hundred thirty-one".