Base | Representation |
---|---|
bin | 100000000110101111111111… |
… | …001100111010110001010011 |
3 | 200111221201022120021102122121 |
4 | 200012233333030322301103 |
5 | 122001420311321320111 |
6 | 1220150555100515111 |
7 | 41512313424005446 |
oct | 4006577714726123 |
9 | 614851276242577 |
10 | 141201331432531 |
11 | 40a9a16a5342a7 |
12 | 13a0592024ba97 |
13 | 60a32c7aba3b6 |
14 | 26c227659965d |
15 | 114ce86025871 |
hex | 806bff33ac53 |
141201331432531 has 2 divisors, whose sum is σ = 141201331432532. Its totient is φ = 141201331432530.
The previous prime is 141201331432507. The next prime is 141201331432543. The reversal of 141201331432531 is 135234133102141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141201331432531 - 29 = 141201331432019 is a prime.
It is a super-2 number, since 2×1412013314325312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141201331402531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70600665716265 + 70600665716266.
It is an arithmetic number, because the mean of its divisors is an integer number (70600665716266).
Almost surely, 2141201331432531 is an apocalyptic number.
141201331432531 is a deficient number, since it is larger than the sum of its proper divisors (1).
141201331432531 is an equidigital number, since it uses as much as digits as its factorization.
141201331432531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 141201331432531 its reverse (135234133102141), we get a palindrome (276435464534672).
The spelling of 141201331432531 in words is "one hundred forty-one trillion, two hundred one billion, three hundred thirty-one million, four hundred thirty-two thousand, five hundred thirty-one".
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