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141202205552503 is a prime number
BaseRepresentation
bin100000000110110000110011…
…010011011010111101110111
3200111221210120111002022211101
4200012300303103122331313
5122001424104110140003
61220151221524150531
741512344166625254
oct4006606323327567
9614853514068741
10141202205552503
1140a9a57899a5a7
1213a05b24b38447
1360a3406c22154
1426c231a6da42b
15114ced7b3e11d
hex806c334daf77

141202205552503 has 2 divisors, whose sum is σ = 141202205552504. Its totient is φ = 141202205552502.

The previous prime is 141202205552413. The next prime is 141202205552531. The reversal of 141202205552503 is 305255502202141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141202205552503 - 29 = 141202205551991 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141202205558503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601102776251 + 70601102776252.

It is an arithmetic number, because the mean of its divisors is an integer number (70601102776252).

Almost surely, 2141202205552503 is an apocalyptic number.

141202205552503 is a deficient number, since it is larger than the sum of its proper divisors (1).

141202205552503 is an equidigital number, since it uses as much as digits as its factorization.

141202205552503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120000, while the sum is 37.

Adding to 141202205552503 its reverse (305255502202141), we get a palindrome (446457707754644).

The spelling of 141202205552503 in words is "one hundred forty-one trillion, two hundred two billion, two hundred five million, five hundred fifty-two thousand, five hundred three".