Base | Representation |
---|---|
bin | 100000000110110000110101… |
… | …000001001010010101011111 |
3 | 200111221210122111012212201111 |
4 | 200012300311001022111133 |
5 | 122001424133441221343 |
6 | 1220151224432522451 |
7 | 41512344666302206 |
oct | 4006606501122537 |
9 | 614853574185644 |
10 | 141202234320223 |
11 | 40a9a59315917a |
12 | 13a05b326b0427 |
13 | 60a340cb8527b |
14 | 26c232046823d |
15 | 114ceda422c9d |
hex | 806c3504a55f |
141202234320223 has 2 divisors, whose sum is σ = 141202234320224. Its totient is φ = 141202234320222.
The previous prime is 141202234320149. The next prime is 141202234320227. The reversal of 141202234320223 is 322023432202141.
It is a strong prime.
It is an emirp because it is prime and its reverse (322023432202141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141202234320223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141202234320227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601117160111 + 70601117160112.
It is an arithmetic number, because the mean of its divisors is an integer number (70601117160112).
Almost surely, 2141202234320223 is an apocalyptic number.
141202234320223 is a deficient number, since it is larger than the sum of its proper divisors (1).
141202234320223 is an equidigital number, since it uses as much as digits as its factorization.
141202234320223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 141202234320223 its reverse (322023432202141), we get a palindrome (463225666522364).
The spelling of 141202234320223 in words is "one hundred forty-one trillion, two hundred two billion, two hundred thirty-four million, three hundred twenty thousand, two hundred twenty-three".
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