Base | Representation |
---|---|
bin | 1000001110000001011… |
… | …1010010000111111001 |
3 | 111111110200122101221021 |
4 | 2003200113102013321 |
5 | 4303141001402101 |
6 | 144511241342441 |
7 | 13126101000112 |
oct | 2034027220771 |
9 | 444420571837 |
10 | 141203153401 |
11 | 5497a5540a2 |
12 | 23448797a21 |
13 | 10413c1b89b |
14 | 6b9733d209 |
15 | 3a166815a1 |
hex | 20e05d21f9 |
141203153401 has 2 divisors, whose sum is σ = 141203153402. Its totient is φ = 141203153400.
The previous prime is 141203153389. The next prime is 141203153419. The reversal of 141203153401 is 104351302141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 140907141376 + 296012025 = 375376^2 + 17205^2 .
It is a cyclic number.
It is not a de Polignac number, because 141203153401 - 223 = 141194764793 is a prime.
It is a super-3 number, since 3×1412031534013 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (141203153101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601576700 + 70601576701.
It is an arithmetic number, because the mean of its divisors is an integer number (70601576701).
Almost surely, 2141203153401 is an apocalyptic number.
It is an amenable number.
141203153401 is a deficient number, since it is larger than the sum of its proper divisors (1).
141203153401 is an equidigital number, since it uses as much as digits as its factorization.
141203153401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 141203153401 its reverse (104351302141), we get a palindrome (245554455542).
The spelling of 141203153401 in words is "one hundred forty-one billion, two hundred three million, one hundred fifty-three thousand, four hundred one".
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