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141211400131093 is a prime number
BaseRepresentation
bin100000000110111001010111…
…010101111101001000010101
3200111222200022021022022111011
4200012321113111331020111
5122002101421413143333
61220155342140012221
741513121064353655
oct4006712725751025
9614880267268434
10141211400131093
1140aa3467000586
1213a07870231071
1360a4240aabbb6
1426c294d8c2365
15114d374e539cd
hex806e5757d215

141211400131093 has 2 divisors, whose sum is σ = 141211400131094. Its totient is φ = 141211400131092.

The previous prime is 141211400131031. The next prime is 141211400131121. The reversal of 141211400131093 is 390131004112141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97012610852004 + 44198789279089 = 9849498^2 + 6648217^2 .

It is an emirp because it is prime and its reverse (390131004112141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141211400131093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141211400131393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70605700065546 + 70605700065547.

It is an arithmetic number, because the mean of its divisors is an integer number (70605700065547).

Almost surely, 2141211400131093 is an apocalyptic number.

It is an amenable number.

141211400131093 is a deficient number, since it is larger than the sum of its proper divisors (1).

141211400131093 is an equidigital number, since it uses as much as digits as its factorization.

141211400131093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 141211400131093 in words is "one hundred forty-one trillion, two hundred eleven billion, four hundred million, one hundred thirty-one thousand, ninety-three".