1412130564641 has 2 divisors, whose sum is σ = 1412130564642. Its totient is φ = 1412130564640.

The previous prime is 1412130564619. The next prime is 1412130564653. The reversal of 1412130564641 is 1464650312141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1412125812241 + 4752400 = 1188329^2 + 2180^2 .

It is an emirp because it is prime and its reverse (1464650312141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1412130564641 - 2³⁰ = 1411056822817 is a prime.

It is a super-2 number, since 2×1412130564641² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1412130564595 and 1412130564604.

It is not a weakly prime, because it can be changed into another prime (1412130564041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706065282320 + 706065282321.

It is an arithmetic number, because the mean of its divisors is an integer number (706065282321).

Almost surely, 2^{1412130564641} is an apocalyptic number.

It is an amenable number.

1412130564641 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412130564641 is an equidigital number, since it uses as much as digits as its factorization.

1412130564641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 38.

Adding to 1412130564641 its reverse (1464650312141), we get a palindrome (2876780876782).

The spelling of 1412130564641 in words is "one trillion, four hundred twelve billion, one hundred thirty million, five hundred sixty-four thousand, six hundred forty-one".