1412130632641 has 2 divisors, whose sum is σ = 1412130632642. Its totient is φ = 1412130632640.

The previous prime is 1412130632609. The next prime is 1412130632681. The reversal of 1412130632641 is 1462360312141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1229169125041 + 182961507600 = 1108679^2 + 427740^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412130632641 - 2⁵ = 1412130632609 is a prime.

It is a super-2 number, since 2×1412130632641² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1412130632597 and 1412130632606.

It is not a weakly prime, because it can be changed into another prime (1412130632681) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706065316320 + 706065316321.

It is an arithmetic number, because the mean of its divisors is an integer number (706065316321).

Almost surely, 2^{1412130632641} is an apocalyptic number.

It is an amenable number.

1412130632641 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412130632641 is an equidigital number, since it uses as much as digits as its factorization.

1412130632641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 34.

Adding to 1412130632641 its reverse (1462360312141), we get a palindrome (2874490944782).

The spelling of 1412130632641 in words is "one trillion, four hundred twelve billion, one hundred thirty million, six hundred thirty-two thousand, six hundred forty-one".