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14121501349 is a prime number
BaseRepresentation
bin11010010011011010…
…10000001010100101
31100110011002121002111
431021231100022211
5212410101020344
610253132441021
71006641531604
oct151155201245
940404077074
1014121501349
115a97245a7a
1228a1319171
131440840277
1497d6a3a3b
15579b33834
hex349b502a5

14121501349 has 2 divisors, whose sum is σ = 14121501350. Its totient is φ = 14121501348.

The previous prime is 14121501341. The next prime is 14121501371. The reversal of 14121501349 is 94310512141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10749957124 + 3371544225 = 103682^2 + 58065^2 .

It is an emirp because it is prime and its reverse (94310512141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14121501349 - 23 = 14121501341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14121501349.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14121501341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060750674 + 7060750675.

It is an arithmetic number, because the mean of its divisors is an integer number (7060750675).

Almost surely, 214121501349 is an apocalyptic number.

It is an amenable number.

14121501349 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121501349 is an equidigital number, since it uses as much as digits as its factorization.

14121501349 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 14121501349 in words is "fourteen billion, one hundred twenty-one million, five hundred one thousand, three hundred forty-nine".