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14121512303 is a prime number
BaseRepresentation
bin11010010011011010…
…10010110101101111
31100110011010011010012
431021231102311233
5212410101343203
610253133003435
71006641605543
oct151155226557
940404104105
1014121512303
115a97253228
1228a132357b
131440845252
1497d6a7a23
15579b36bd8
hex349b52d6f

14121512303 has 2 divisors, whose sum is σ = 14121512304. Its totient is φ = 14121512302.

The previous prime is 14121512287. The next prime is 14121512311. The reversal of 14121512303 is 30321512141.

It is a strong prime.

It is an emirp because it is prime and its reverse (30321512141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14121512303 - 24 = 14121512287 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14121532303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060756151 + 7060756152.

It is an arithmetic number, because the mean of its divisors is an integer number (7060756152).

Almost surely, 214121512303 is an apocalyptic number.

14121512303 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121512303 is an equidigital number, since it uses as much as digits as its factorization.

14121512303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

The spelling of 14121512303 in words is "fourteen billion, one hundred twenty-one million, five hundred twelve thousand, three hundred three".