Base | Representation |
---|---|
bin | 11010010011011110… |
… | …01000100001100111 |
3 | 1100110012000122100112 |
4 | 31021233020201213 |
5 | 212410212304333 |
6 | 10253151203235 |
7 | 1006645654112 |
oct | 151157104147 |
9 | 40405018315 |
10 | 14121994343 |
11 | 5a97552406 |
12 | 28a151651b |
13 | 1440983792 |
14 | 97d791579 |
15 | 579bce948 |
hex | 349bc8867 |
14121994343 has 2 divisors, whose sum is σ = 14121994344. Its totient is φ = 14121994342.
The previous prime is 14121994307. The next prime is 14121994373. The reversal of 14121994343 is 34349912141.
14121994343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14121994343 - 26 = 14121994279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14121994343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14121994373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060997171 + 7060997172.
It is an arithmetic number, because the mean of its divisors is an integer number (7060997172).
Almost surely, 214121994343 is an apocalyptic number.
14121994343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14121994343 is an equidigital number, since it uses as much as digits as its factorization.
14121994343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 41.
The spelling of 14121994343 in words is "fourteen billion, one hundred twenty-one million, nine hundred ninety-four thousand, three hundred forty-three".
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