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141221112112321 is a prime number
BaseRepresentation
bin100000000111000010011010…
…001110001110010011000001
3200112000121101010010002010121
4200013002122032032103001
5122002231314200043241
61220204025553300241
741513613544010023
oct4007023216162301
9615017333102117
10141221112112321
1140aa75a018484a
1213a09720864681
1360a512ac04b57
1426c31d16b0013
15114d7428bcad1
hex80709a38e4c1

141221112112321 has 2 divisors, whose sum is σ = 141221112112322. Its totient is φ = 141221112112320.

The previous prime is 141221112112291. The next prime is 141221112112349. The reversal of 141221112112321 is 123211211122141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130342751400625 + 10878360711696 = 11416775^2 + 3298236^2 .

It is an emirp because it is prime and its reverse (123211211122141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141221112112321 - 27 = 141221112112193 is a prime.

It is not a weakly prime, because it can be changed into another prime (141221112112361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70610556056160 + 70610556056161.

It is an arithmetic number, because the mean of its divisors is an integer number (70610556056161).

Almost surely, 2141221112112321 is an apocalyptic number.

It is an amenable number.

141221112112321 is a deficient number, since it is larger than the sum of its proper divisors (1).

141221112112321 is an equidigital number, since it uses as much as digits as its factorization.

141221112112321 is an evil number, because the sum of its binary digits is even.

The product of its digits is 384, while the sum is 25.

Adding to 141221112112321 its reverse (123211211122141), we get a palindrome (264432323234462).

The spelling of 141221112112321 in words is "one hundred forty-one trillion, two hundred twenty-one billion, one hundred twelve million, one hundred twelve thousand, three hundred twenty-one".