Base | Representation |
---|---|
bin | 1000001110000101101… |
… | …1110101000001101001 |
3 | 111111111221110022102121 |
4 | 2003201123311001221 |
5 | 4303210101402103 |
6 | 144513122431241 |
7 | 13126406506126 |
oct | 2034133650151 |
9 | 444457408377 |
10 | 141221122153 |
11 | 54989707301 |
12 | 23452802521 |
13 | 10417870597 |
14 | 6b9989974d |
15 | 3a180306bd |
hex | 20e16f5069 |
141221122153 has 2 divisors, whose sum is σ = 141221122154. Its totient is φ = 141221122152.
The previous prime is 141221122121. The next prime is 141221122247. The reversal of 141221122153 is 351221122141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127965744729 + 13255377424 = 357723^2 + 115132^2 .
It is a cyclic number.
It is not a de Polignac number, because 141221122153 - 25 = 141221122121 is a prime.
It is not a weakly prime, because it can be changed into another prime (141221122253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70610561076 + 70610561077.
It is an arithmetic number, because the mean of its divisors is an integer number (70610561077).
Almost surely, 2141221122153 is an apocalyptic number.
It is an amenable number.
141221122153 is a deficient number, since it is larger than the sum of its proper divisors (1).
141221122153 is an equidigital number, since it uses as much as digits as its factorization.
141221122153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 960, while the sum is 25.
Adding to 141221122153 its reverse (351221122141), we get a palindrome (492442244294).
The spelling of 141221122153 in words is "one hundred forty-one billion, two hundred twenty-one million, one hundred twenty-two thousand, one hundred fifty-three".
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