141222113 has 2 divisors, whose sum is σ = 141222114. Its totient is φ = 141222112.

The previous prime is 141222097. The next prime is 141222119. The reversal of 141222113 is 311222141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140944384 + 277729 = 11872^2 + 527^2 .

It is a cyclic number.

It is not a de Polignac number, because 141222113 - 2⁴ = 141222097 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 141222091 and 141222100.

It is not a weakly prime, because it can be changed into another prime (141222119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70611056 + 70611057.

It is an arithmetic number, because the mean of its divisors is an integer number (70611057).

Almost surely, 2^141222113 is an apocalyptic number.

It is an amenable number.

141222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141222113 is an equidigital number, since it uses as much as digits as its factorization.

141222113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 17.

The square root of 141222113 is about 11883.6910511844. The cubic root of 141222113 is about 520.7559431779.

Adding to 141222113 its reverse (311222141), we get a palindrome (452444254).

The spelling of 141222113 in words is "one hundred forty-one million, two hundred twenty-two thousand, one hundred thirteen".