Base | Representation |
---|---|
bin | 1100110110000001011000… |
… | …0010011111101101000111 |
3 | 1212000001220221121010222002 |
4 | 3031200112002133231013 |
5 | 3322334302342102101 |
6 | 50011354225255515 |
7 | 2655203555164541 |
oct | 315402602375507 |
9 | 55001827533862 |
10 | 14122222222151 |
11 | 455522330813a |
12 | 1700b9379459b |
13 | 7b5948650664 |
14 | 36b73a998691 |
15 | 19754100ed6b |
hex | cd81609fb47 |
14122222222151 has 2 divisors, whose sum is σ = 14122222222152. Its totient is φ = 14122222222150.
The previous prime is 14122222222103. The next prime is 14122222222177. The reversal of 14122222222151 is 15122222222141.
14122222222151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14122222222151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14122222222951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061111111075 + 7061111111076.
It is an arithmetic number, because the mean of its divisors is an integer number (7061111111076).
Almost surely, 214122222222151 is an apocalyptic number.
14122222222151 is a deficient number, since it is larger than the sum of its proper divisors (1).
14122222222151 is an equidigital number, since it uses as much as digits as its factorization.
14122222222151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5120, while the sum is 29.
Adding to 14122222222151 its reverse (15122222222141), we get a palindrome (29244444444292).
The spelling of 14122222222151 in words is "fourteen trillion, one hundred twenty-two billion, two hundred twenty-two million, two hundred twenty-two thousand, one hundred fifty-one".
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