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141222343244207 is a prime number
BaseRepresentation
bin100000000111000011100011…
…100110100111100110101111
3200112000201112220201001120212
4200013003203212213212233
5122002241324332303312
61220204352052533035
741513656213316561
oct4007034346474657
9615021486631525
10141222343244207
1140aa8072114415
1213a09a0502117b
1360a5295ca9564
1426c32aadc5331
15114d7b5a07822
hex8070e39a79af

141222343244207 has 2 divisors, whose sum is σ = 141222343244208. Its totient is φ = 141222343244206.

The previous prime is 141222343244201. The next prime is 141222343244309. The reversal of 141222343244207 is 702442343222141.

141222343244207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141222343244207 - 210 = 141222343243183 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141222343244201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70611171622103 + 70611171622104.

It is an arithmetic number, because the mean of its divisors is an integer number (70611171622104).

Almost surely, 2141222343244207 is an apocalyptic number.

141222343244207 is a deficient number, since it is larger than the sum of its proper divisors (1).

141222343244207 is an equidigital number, since it uses as much as digits as its factorization.

141222343244207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 516096, while the sum is 41.

Adding to 141222343244207 its reverse (702442343222141), we get a palindrome (843664686466348).

The spelling of 141222343244207 in words is "one hundred forty-one trillion, two hundred twenty-two billion, three hundred forty-three million, two hundred forty-four thousand, two hundred seven".