Base | Representation |
---|---|
bin | 100000000111000011100011… |
… | …100110100111101000001111 |
3 | 200112000201112220201001201102 |
4 | 200013003203212213220033 |
5 | 122002241324332304203 |
6 | 1220204352052533315 |
7 | 41513656213320056 |
oct | 4007034346475017 |
9 | 615021486631642 |
10 | 141222343244303 |
11 | 40aa80721144a2 |
12 | 13a09a0502123b |
13 | 60a5295ca9609 |
14 | 26c32aadc539d |
15 | 114d7b5a07888 |
hex | 8070e39a7a0f |
141222343244303 has 4 divisors (see below), whose sum is σ = 141222438074688. Its totient is φ = 141222248413920.
The previous prime is 141222343244207. The next prime is 141222343244309. The reversal of 141222343244303 is 303442343222141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141222343244303 - 218 = 141222342982159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141222343244309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45145151 + ... + 48171872.
It is an arithmetic number, because the mean of its divisors is an integer number (35305609518672).
Almost surely, 2141222343244303 is an apocalyptic number.
141222343244303 is a deficient number, since it is larger than the sum of its proper divisors (94830385).
141222343244303 is an equidigital number, since it uses as much as digits as its factorization.
141222343244303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94830384.
The product of its (nonzero) digits is 331776, while the sum is 38.
Adding to 141222343244303 its reverse (303442343222141), we get a palindrome (444664686466444).
The spelling of 141222343244303 in words is "one hundred forty-one trillion, two hundred twenty-two billion, three hundred forty-three million, two hundred forty-four thousand, three hundred three".
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