Base | Representation |
---|---|
bin | 100000000111000011101001… |
… | …000001101101010000011011 |
3 | 200112000201210020220200110001 |
4 | 200013003221001231100123 |
5 | 122002242021130400243 |
6 | 1220204405103033431 |
7 | 41513661366563254 |
oct | 4007035101552033 |
9 | 615021706820401 |
10 | 141222434231323 |
11 | 40aa810950a385 |
12 | 13a09a2b59b877 |
13 | 60a52abab58a3 |
14 | 26c32b910bb2b |
15 | 114d7bd9cba4d |
hex | 8070e906d41b |
141222434231323 has 2 divisors, whose sum is σ = 141222434231324. Its totient is φ = 141222434231322.
The previous prime is 141222434231321. The next prime is 141222434231339. The reversal of 141222434231323 is 323132434222141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141222434231323 - 21 = 141222434231321 is a prime.
Together with 141222434231321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (141222434231321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70611217115661 + 70611217115662.
It is an arithmetic number, because the mean of its divisors is an integer number (70611217115662).
Almost surely, 2141222434231323 is an apocalyptic number.
141222434231323 is a deficient number, since it is larger than the sum of its proper divisors (1).
141222434231323 is an equidigital number, since it uses as much as digits as its factorization.
141222434231323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 165888, while the sum is 37.
Adding to 141222434231323 its reverse (323132434222141), we get a palindrome (464354868453464).
The spelling of 141222434231323 in words is "one hundred forty-one trillion, two hundred twenty-two billion, four hundred thirty-four million, two hundred thirty-one thousand, three hundred twenty-three".
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