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14122413101 is a prime number
BaseRepresentation
bin11010010011100001…
…01110110000101101
31100110012210220210002
431021300232300231
5212410314204401
610253204154045
71006652350016
oct151160566055
940405726702
1014122413101
115a97808a95
1228a1698925
131440a9c274
1497d86000d
15579c63a6b
hex349c2ec2d

14122413101 has 2 divisors, whose sum is σ = 14122413102. Its totient is φ = 14122413100.

The previous prime is 14122413013. The next prime is 14122413131. The reversal of 14122413101 is 10131422141.

14122413101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11422051876 + 2700361225 = 106874^2 + 51965^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14122413101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14122413131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061206550 + 7061206551.

It is an arithmetic number, because the mean of its divisors is an integer number (7061206551).

Almost surely, 214122413101 is an apocalyptic number.

It is an amenable number.

14122413101 is a deficient number, since it is larger than the sum of its proper divisors (1).

14122413101 is an equidigital number, since it uses as much as digits as its factorization.

14122413101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14122413101 its reverse (10131422141), we get a palindrome (24253835242).

The spelling of 14122413101 in words is "fourteen billion, one hundred twenty-two million, four hundred thirteen thousand, one hundred one".