Base | Representation |
---|---|
bin | 1000001110000110101… |
… | …1000011110101111011 |
3 | 111111112012222011120221 |
4 | 2003201223003311323 |
5 | 4303212112140003 |
6 | 144513344200511 |
7 | 13126455446110 |
oct | 2034153036573 |
9 | 444465864527 |
10 | 141225115003 |
11 | 54990994185 |
12 | 23454009137 |
13 | 1041863ab0b |
14 | 6b9a218907 |
15 | 3a1856d7bd |
hex | 20e1ac3d7b |
141225115003 has 32 divisors (see below), whose sum is σ = 165597696000. Its totient is φ = 117940860960.
The previous prime is 141225114937. The next prime is 141225115033. The reversal of 141225115003 is 300511522141.
It is a cyclic number.
It is not a de Polignac number, because 141225115003 - 29 = 141225114491 is a prime.
It is a super-3 number, since 3×1412251150033 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141225115033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 71360868 + ... + 71362846.
It is an arithmetic number, because the mean of its divisors is an integer number (5174928000).
Almost surely, 2141225115003 is an apocalyptic number.
141225115003 is a deficient number, since it is larger than the sum of its proper divisors (24372580997).
141225115003 is a wasteful number, since it uses less digits than its factorization.
141225115003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3495.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 141225115003 its reverse (300511522141), we get a palindrome (441736637144).
The spelling of 141225115003 in words is "one hundred forty-one billion, two hundred twenty-five million, one hundred fifteen thousand, three".
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