Base | Representation |
---|---|
bin | 100000000111001010110011… |
… | …010000010001000101101000 |
3 | 200112001110122000211110100221 |
4 | 200013022303100101011220 |
5 | 122002403242213404112 |
6 | 1220212120010535424 |
7 | 41514353036625103 |
oct | 4007126320210550 |
9 | 615043560743327 |
10 | 141230122013032 |
11 | 410003a4018588 |
12 | 13a0b416137574 |
13 | 60a5c35740750 |
14 | 26c380814173a |
15 | 114dabd8a2e07 |
hex | 8072b3411168 |
141230122013032 has 32 divisors (see below), whose sum is σ = 285177241399680. Its totient is φ = 65182897010880.
The previous prime is 141230122013011. The next prime is 141230122013069. The reversal of 141230122013032 is 230310221032141.
It is a junction number, because it is equal to n+sod(n) for n = 141230122012988 and 141230122013006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28202853 + ... + 32830795.
It is an arithmetic number, because the mean of its divisors is an integer number (8911788793740).
Almost surely, 2141230122013032 is an apocalyptic number.
It is an amenable number.
141230122013032 is an abundant number, since it is smaller than the sum of its proper divisors (143947119386648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141230122013032 is a wasteful number, since it uses less digits than its factorization.
141230122013032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4921393 (or 4921389 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 141230122013032 its reverse (230310221032141), we get a palindrome (371540343045173).
The spelling of 141230122013032 in words is "one hundred forty-one trillion, two hundred thirty billion, one hundred twenty-two million, thirteen thousand, thirty-two".
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