Base | Representation |
---|---|
bin | 1100110110000101100000… |
… | …0101111100110110010011 |
3 | 1212000011210011212122101211 |
4 | 3031201120011330312103 |
5 | 3322344040042033321 |
6 | 50012100214040551 |
7 | 2655243202561411 |
oct | 315413005746623 |
9 | 55004704778354 |
10 | 14123330424211 |
11 | 4555741914808 |
12 | 1701242949157 |
13 | 7b5a94113718 |
14 | 36b803c302b1 |
15 | 1975a84660e1 |
hex | cd85817cd93 |
14123330424211 has 2 divisors, whose sum is σ = 14123330424212. Its totient is φ = 14123330424210.
The previous prime is 14123330424193. The next prime is 14123330424311. The reversal of 14123330424211 is 11242403332141.
It is a happy number.
14123330424211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14123330424211 - 25 = 14123330424179 is a prime.
It is not a weakly prime, because it can be changed into another prime (14123330424311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061665212105 + 7061665212106.
It is an arithmetic number, because the mean of its divisors is an integer number (7061665212106).
Almost surely, 214123330424211 is an apocalyptic number.
14123330424211 is a deficient number, since it is larger than the sum of its proper divisors (1).
14123330424211 is an equidigital number, since it uses as much as digits as its factorization.
14123330424211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 14123330424211 its reverse (11242403332141), we get a palindrome (25365733756352).
The spelling of 14123330424211 in words is "fourteen trillion, one hundred twenty-three billion, three hundred thirty million, four hundred twenty-four thousand, two hundred eleven".
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