Base | Representation |
---|---|
bin | 1000001110001000110… |
… | …0111101110111101001 |
3 | 111111112211200202020001 |
4 | 2003202030331313221 |
5 | 4303221401102213 |
6 | 144514302503001 |
7 | 13126624135645 |
oct | 2034214756751 |
9 | 444484622201 |
10 | 141234003433 |
11 | 54995a05196 |
12 | 23456b94a61 |
13 | 1041a430743 |
14 | 6b9b48dc25 |
15 | 3a192271dd |
hex | 20e233dde9 |
141234003433 has 2 divisors, whose sum is σ = 141234003434. Its totient is φ = 141234003432.
The previous prime is 141234003403. The next prime is 141234003461. The reversal of 141234003433 is 334300432141.
It is an a-pointer prime, because the next prime (141234003461) can be obtained adding 141234003433 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95108709609 + 46125293824 = 308397^2 + 214768^2 .
It is a cyclic number.
It is not a de Polignac number, because 141234003433 - 217 = 141233872361 is a prime.
It is not a weakly prime, because it can be changed into another prime (141234003403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70617001716 + 70617001717.
It is an arithmetic number, because the mean of its divisors is an integer number (70617001717).
Almost surely, 2141234003433 is an apocalyptic number.
It is an amenable number.
141234003433 is a deficient number, since it is larger than the sum of its proper divisors (1).
141234003433 is an equidigital number, since it uses as much as digits as its factorization.
141234003433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 141234003433 its reverse (334300432141), we get a palindrome (475534435574).
The spelling of 141234003433 in words is "one hundred forty-one billion, two hundred thirty-four million, three thousand, four hundred thirty-three".
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