Base | Representation |
---|---|
bin | 10100100011010110010… |
… | …101111011010000101111 |
3 | 12000000111202221022012111 |
4 | 110203112111323100233 |
5 | 141114440402020241 |
6 | 3000453354144451 |
7 | 204016143232513 |
oct | 24432625732057 |
9 | 5000452838174 |
10 | 1412345345071 |
11 | 4a4a77144811 |
12 | 1a987b722127 |
13 | a3250484b9b |
14 | 4c502042143 |
15 | 26b11d99c81 |
hex | 148d657b42f |
1412345345071 has 2 divisors, whose sum is σ = 1412345345072. Its totient is φ = 1412345345070.
The previous prime is 1412345344939. The next prime is 1412345345093. The reversal of 1412345345071 is 1705435432141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1412345345071 - 213 = 1412345336879 is a prime.
It is a super-3 number, since 3×14123453450713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412345345771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706172672535 + 706172672536.
It is an arithmetic number, because the mean of its divisors is an integer number (706172672536).
Almost surely, 21412345345071 is an apocalyptic number.
1412345345071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412345345071 is an equidigital number, since it uses as much as digits as its factorization.
1412345345071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 40.
The spelling of 1412345345071 in words is "one trillion, four hundred twelve billion, three hundred forty-five million, three hundred forty-five thousand, seventy-one".
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