Base | Representation |
---|---|
bin | 100000000111010101000001… |
… | …101110000001101001111011 |
3 | 200112002111222020211100110001 |
4 | 200013111001232001221323 |
5 | 122003043234120112103 |
6 | 1220221133324333431 |
7 | 41515222115140405 |
oct | 4007250156015173 |
9 | 615074866740401 |
10 | 141241102113403 |
11 | 41005018aa44a6 |
12 | 13a1157b3a4277 |
13 | 60a6c954bb566 |
14 | 26c416a511b75 |
15 | 114e01281101d |
hex | 807541b81a7b |
141241102113403 has 2 divisors, whose sum is σ = 141241102113404. Its totient is φ = 141241102113402.
The previous prime is 141241102113401. The next prime is 141241102113427. The reversal of 141241102113403 is 304311201142141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141241102113403 - 21 = 141241102113401 is a prime.
Together with 141241102113401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (141241102113401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70620551056701 + 70620551056702.
It is an arithmetic number, because the mean of its divisors is an integer number (70620551056702).
Almost surely, 2141241102113403 is an apocalyptic number.
141241102113403 is a deficient number, since it is larger than the sum of its proper divisors (1).
141241102113403 is an equidigital number, since it uses as much as digits as its factorization.
141241102113403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 141241102113403 its reverse (304311201142141), we get a palindrome (445552303255544).
The spelling of 141241102113403 in words is "one hundred forty-one trillion, two hundred forty-one billion, one hundred two million, one hundred thirteen thousand, four hundred three".
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