Base | Representation |
---|---|
bin | 100000000111010101000010… |
… | …010111111110011010111011 |
3 | 200112002112000000112001012221 |
4 | 200013111002113332122323 |
5 | 122003043244424011303 |
6 | 1220221134400144511 |
7 | 41515222310461141 |
oct | 4007250227763273 |
9 | 615075000461187 |
10 | 141241113110203 |
11 | 41005024225567 |
12 | 13a11583008137 |
13 | 60a6c9786ba42 |
14 | 26c416bb75591 |
15 | 114e0137844bd |
hex | 8075425fe6bb |
141241113110203 has 2 divisors, whose sum is σ = 141241113110204. Its totient is φ = 141241113110202.
The previous prime is 141241113110197. The next prime is 141241113110219. The reversal of 141241113110203 is 302011311142141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141241113110203 - 25 = 141241113110171 is a prime.
It is not a weakly prime, because it can be changed into another prime (141241113110003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70620556555101 + 70620556555102.
It is an arithmetic number, because the mean of its divisors is an integer number (70620556555102).
Almost surely, 2141241113110203 is an apocalyptic number.
141241113110203 is a deficient number, since it is larger than the sum of its proper divisors (1).
141241113110203 is an equidigital number, since it uses as much as digits as its factorization.
141241113110203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 141241113110203 its reverse (302011311142141), we get a palindrome (443252424252344).
The spelling of 141241113110203 in words is "one hundred forty-one trillion, two hundred forty-one billion, one hundred thirteen million, one hundred ten thousand, two hundred three".
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