Base | Representation |
---|---|
bin | 1000001110001010110… |
… | …1110011001111000111 |
3 | 111111120102220001002011 |
4 | 2003202231303033013 |
5 | 4303231102020011 |
6 | 144515211155051 |
7 | 13130060244553 |
oct | 2034255631707 |
9 | 444512801064 |
10 | 141242610631 |
11 | 5499a853981 |
12 | 23459a45a87 |
13 | 1041c155365 |
14 | 6b9c690863 |
15 | 3a19d77621 |
hex | 20e2b733c7 |
141242610631 has 2 divisors, whose sum is σ = 141242610632. Its totient is φ = 141242610630.
The previous prime is 141242610599. The next prime is 141242610673. The reversal of 141242610631 is 136016242141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141242610631 - 25 = 141242610599 is a prime.
It is a super-2 number, since 2×1412426106312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141242610593 and 141242610602.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141242640631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70621305315 + 70621305316.
It is an arithmetic number, because the mean of its divisors is an integer number (70621305316).
Almost surely, 2141242610631 is an apocalyptic number.
141242610631 is a deficient number, since it is larger than the sum of its proper divisors (1).
141242610631 is an equidigital number, since it uses as much as digits as its factorization.
141242610631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 141242610631 its reverse (136016242141), we get a palindrome (277258852772).
The spelling of 141242610631 in words is "one hundred forty-one billion, two hundred forty-two million, six hundred ten thousand, six hundred thirty-one".
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