Search a number
-
+
14124550311253 is a prime number
BaseRepresentation
bin1100110110001010000011…
…0011011100110101010101
31212000021221012022022211101
43031202200303130311111
53322404034334430003
650012421232310101
72655315344465404
oct315424063346525
955007835268741
1014124550311253
114556208473a18
1217015233a2331
137b5c29a7ba85
1436b8bbc5963b
1519762a5ce11d
hexcd8a0cdcd55

14124550311253 has 2 divisors, whose sum is σ = 14124550311254. Its totient is φ = 14124550311252.

The previous prime is 14124550311097. The next prime is 14124550311401. The reversal of 14124550311253 is 35211305542141.

14124550311253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8408735647524 + 5715814663729 = 2899782^2 + 2390777^2 .

It is a cyclic number.

It is not a de Polignac number, because 14124550311253 - 237 = 13987111357781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14124550311953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062275155626 + 7062275155627.

It is an arithmetic number, because the mean of its divisors is an integer number (7062275155627).

Almost surely, 214124550311253 is an apocalyptic number.

It is an amenable number.

14124550311253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14124550311253 is an equidigital number, since it uses as much as digits as its factorization.

14124550311253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 14124550311253 its reverse (35211305542141), we get a palindrome (49335855853394).

The spelling of 14124550311253 in words is "fourteen trillion, one hundred twenty-four billion, five hundred fifty million, three hundred eleven thousand, two hundred fifty-three".