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1412462153407 is a prime number
BaseRepresentation
bin10100100011011101010…
…011100000111010111111
312000000210220201210010011
4110203131103200322333
5141120210302402112
63000513125524051
7204022062131554
oct24433523407277
95000726653104
101412462153407
114a5027076628
121a98b2873627
13a326b732146
144c51376aa2b
1526b1c26eaa7
hex148dd4e0ebf

1412462153407 has 2 divisors, whose sum is σ = 1412462153408. Its totient is φ = 1412462153406.

The previous prime is 1412462153369. The next prime is 1412462153449. The reversal of 1412462153407 is 7043512642141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1412462153407 - 239 = 862706339519 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1412462153407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412462153467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706231076703 + 706231076704.

It is an arithmetic number, because the mean of its divisors is an integer number (706231076704).

Almost surely, 21412462153407 is an apocalyptic number.

1412462153407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412462153407 is an equidigital number, since it uses as much as digits as its factorization.

1412462153407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 40.

Adding to 1412462153407 its reverse (7043512642141), we get a palindrome (8455974795548).

The spelling of 1412462153407 in words is "one trillion, four hundred twelve billion, four hundred sixty-two million, one hundred fifty-three thousand, four hundred seven".