Base | Representation |
---|---|
bin | 1100110110001011110000… |
… | …1101000001100111011111 |
3 | 1212000100010020021221201112 |
4 | 3031202330031001213133 |
5 | 3322411010030002401 |
6 | 50012535013132235 |
7 | 2655332626001015 |
oct | 315427415014737 |
9 | 55010106257645 |
10 | 14125010000351 |
11 | 45564239a8168 |
12 | 170163132a07b |
13 | 7b5ca108b963 |
14 | 36b922d1a8b5 |
15 | 197655b333bb |
hex | cd8bc3419df |
14125010000351 has 2 divisors, whose sum is σ = 14125010000352. Its totient is φ = 14125010000350.
The previous prime is 14125010000341. The next prime is 14125010000389. The reversal of 14125010000351 is 15300001052141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14125010000351 - 226 = 14124942891487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14125010000341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062505000175 + 7062505000176.
It is an arithmetic number, because the mean of its divisors is an integer number (7062505000176).
Almost surely, 214125010000351 is an apocalyptic number.
14125010000351 is a deficient number, since it is larger than the sum of its proper divisors (1).
14125010000351 is an equidigital number, since it uses as much as digits as its factorization.
14125010000351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 14125010000351 its reverse (15300001052141), we get a palindrome (29425011052492).
The spelling of 14125010000351 in words is "fourteen trillion, one hundred twenty-five billion, ten million, three hundred fifty-one", and thus it is an aban number.
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