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14125010104477 is a prime number
BaseRepresentation
bin1100110110001011110000…
…1101011011000010011101
31212000100010020111020120001
43031202330031123002131
53322411010041320402
650012535015254301
72655332626613416
oct315427415330235
955010106436501
1014125010104477
114556423a69418
12170163137a391
137b5ca10c717c
1436b922d4680d
15197655b54187
hexcd8bc35b09d

14125010104477 has 2 divisors, whose sum is σ = 14125010104478. Its totient is φ = 14125010104476.

The previous prime is 14125010104421. The next prime is 14125010104511. The reversal of 14125010104477 is 77440101052141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13532200960996 + 592809143481 = 3678614^2 + 769941^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14125010104477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14125010102477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062505052238 + 7062505052239.

It is an arithmetic number, because the mean of its divisors is an integer number (7062505052239).

Almost surely, 214125010104477 is an apocalyptic number.

It is an amenable number.

14125010104477 is a deficient number, since it is larger than the sum of its proper divisors (1).

14125010104477 is an equidigital number, since it uses as much as digits as its factorization.

14125010104477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31360, while the sum is 37.

The spelling of 14125010104477 in words is "fourteen trillion, one hundred twenty-five billion, ten million, one hundred four thousand, four hundred seventy-seven".