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14125014503 is a prime number
BaseRepresentation
bin11010010011110101…
…01001110111100111
31100110101201002020022
431021322221313213
5212412000431003
610253340025355
71010013433205
oct151172516747
940411632208
1014125014503
115a99225506
1228a253225b
1314414a0362
1497dd3a075
1557a0c9738
hex349ea9de7

14125014503 has 2 divisors, whose sum is σ = 14125014504. Its totient is φ = 14125014502.

The previous prime is 14125014473. The next prime is 14125014511. The reversal of 14125014503 is 30541052141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14125014503 - 210 = 14125013479 is a prime.

It is a Sophie Germain prime.

It is an alternating number because its digits alternate between odd and even.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14125014103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062507251 + 7062507252.

It is an arithmetic number, because the mean of its divisors is an integer number (7062507252).

Almost surely, 214125014503 is an apocalyptic number.

14125014503 is a deficient number, since it is larger than the sum of its proper divisors (1).

14125014503 is an equidigital number, since it uses as much as digits as its factorization.

14125014503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 14125014503 its reverse (30541052141), we get a palindrome (44666066644).

The spelling of 14125014503 in words is "fourteen billion, one hundred twenty-five million, fourteen thousand, five hundred three".