Base | Representation |
---|---|
bin | 1000001110001100101… |
… | …1111110011001001111 |
3 | 111111120222202220121000 |
4 | 2003203023332121033 |
5 | 4303240113130110 |
6 | 144520052511343 |
7 | 13130214421056 |
oct | 2034313763117 |
9 | 444528686530 |
10 | 141250520655 |
11 | 549a4266892 |
12 | 2346061b553 |
13 | 1042099484a |
14 | 6b9d74d39d |
15 | 3a1a8db1c0 |
hex | 20e32fe64f |
141250520655 has 64 divisors (see below), whose sum is σ = 262145157120. Its totient is φ = 72026558208.
The previous prime is 141250520633. The next prime is 141250520657. The reversal of 141250520655 is 556025052141.
141250520655 is a `hidden beast` number, since 1 + 4 + 125 + 0 + 520 + 6 + 5 + 5 = 666.
It is not a de Polignac number, because 141250520655 - 29 = 141250520143 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141250520657) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8117094 + ... + 8134476.
It is an arithmetic number, because the mean of its divisors is an integer number (4096018080).
Almost surely, 2141250520655 is an apocalyptic number.
141250520655 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
141250520655 is a deficient number, since it is larger than the sum of its proper divisors (120894636465).
141250520655 is a wasteful number, since it uses less digits than its factorization.
141250520655 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20037 (or 20031 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
Adding to 141250520655 its reverse (556025052141), we get a palindrome (697275572796).
The spelling of 141250520655 in words is "one hundred forty-one billion, two hundred fifty million, five hundred twenty thousand, six hundred fifty-five".
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