14126018113 has 2 divisors, whose sum is σ = 14126018114. Its totient is φ = 14126018112.

The previous prime is 14126018111. The next prime is 14126018143. The reversal of 14126018113 is 31181062141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14102037504 + 23980609 = 118752^2 + 4897^2 .

It is an emirp because it is prime and its reverse (31181062141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14126018113 - 2¹ = 14126018111 is a prime.

Together with 14126018111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14126018111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7063009056 + 7063009057.

It is an arithmetic number, because the mean of its divisors is an integer number (7063009057).

Almost surely, 2^14126018113 is an apocalyptic number.

It is an amenable number.

14126018113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14126018113 is an equidigital number, since it uses as much as digits as its factorization.

14126018113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 28.

The spelling of 14126018113 in words is "fourteen billion, one hundred twenty-six million, eighteen thousand, one hundred thirteen".