Base | Representation |
---|---|
bin | 1100110110011110010111… |
… | …0101010110010110101011 |
3 | 1212000211000020021011001221 |
4 | 3031213211311112112223 |
5 | 3323001221332413303 |
6 | 50015122311122511 |
7 | 2655600441143521 |
oct | 315474565262653 |
9 | 55024006234057 |
10 | 14130003404203 |
11 | 455855660a405 |
12 | 17025a5673437 |
13 | 7b65b874b0ab |
14 | 36bc78182311 |
15 | 1978491d54bd |
hex | cd9e5d565ab |
14130003404203 has 2 divisors, whose sum is σ = 14130003404204. Its totient is φ = 14130003404202.
The previous prime is 14130003404197. The next prime is 14130003404249. The reversal of 14130003404203 is 30240430003141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14130003404203 is a prime.
It is not a weakly prime, because it can be changed into another prime (14130003404903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065001702101 + 7065001702102.
It is an arithmetic number, because the mean of its divisors is an integer number (7065001702102).
Almost surely, 214130003404203 is an apocalyptic number.
14130003404203 is a deficient number, since it is larger than the sum of its proper divisors (1).
14130003404203 is an equidigital number, since it uses as much as digits as its factorization.
14130003404203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 14130003404203 its reverse (30240430003141), we get a palindrome (44370433407344).
The spelling of 14130003404203 in words is "fourteen trillion, one hundred thirty billion, three million, four hundred four thousand, two hundred three".
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