Base | Representation |
---|---|
bin | 1000001110011000110… |
… | …1000101101000101111 |
3 | 111111201112000211220211 |
4 | 2003212031011220233 |
5 | 4303341043102421 |
6 | 144525101523251 |
7 | 13131400623241 |
oct | 2034615055057 |
9 | 444645024824 |
10 | 141301144111 |
11 | 54a1a8a2a56 |
12 | 23475573527 |
13 | 1042b30a95a |
14 | 6ba636a091 |
15 | 3a2008a9e1 |
hex | 20e6345a2f |
141301144111 has 2 divisors, whose sum is σ = 141301144112. Its totient is φ = 141301144110.
The previous prime is 141301144097. The next prime is 141301144121. The reversal of 141301144111 is 111441103141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141301144111 - 25 = 141301144079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141301144121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70650572055 + 70650572056.
It is an arithmetic number, because the mean of its divisors is an integer number (70650572056).
Almost surely, 2141301144111 is an apocalyptic number.
141301144111 is a deficient number, since it is larger than the sum of its proper divisors (1).
141301144111 is an equidigital number, since it uses as much as digits as its factorization.
141301144111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 141301144111 its reverse (111441103141), we get a palindrome (252742247252).
The spelling of 141301144111 in words is "one hundred forty-one billion, three hundred one million, one hundred forty-four thousand, one hundred eleven".
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