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14130131341 is a prime number
BaseRepresentation
bin11010010100011100…
…01011000110001101
31100110202100001012211
431022032023012031
5212414303200331
610254041430421
71010105064124
oct151216130615
940422301184
1014130131341
115aa10aa8a7
1228a419b411
131442572381
149808acabb
1557a78a8b1
hex34a38b18d

14130131341 has 2 divisors, whose sum is σ = 14130131342. Its totient is φ = 14130131340.

The previous prime is 14130131333. The next prime is 14130131347. The reversal of 14130131341 is 14313103141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13594394025 + 535737316 = 116595^2 + 23146^2 .

It is an emirp because it is prime and its reverse (14313103141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14130131341 - 23 = 14130131333 is a prime.

It is a super-2 number, since 2×141301313412 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14130131347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065065670 + 7065065671.

It is an arithmetic number, because the mean of its divisors is an integer number (7065065671).

Almost surely, 214130131341 is an apocalyptic number.

It is an amenable number.

14130131341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14130131341 is an equidigital number, since it uses as much as digits as its factorization.

14130131341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 14130131341 its reverse (14313103141), we get a palindrome (28443234482).

The spelling of 14130131341 in words is "fourteen billion, one hundred thirty million, one hundred thirty-one thousand, three hundred forty-one".