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14130524532541 is a prime number
BaseRepresentation
bin1100110110100000010011…
…1001010010111100111101
31212000212100112212012202111
43031220010321102330331
53323003303240020131
650015250124454021
72655616366516234
oct315500471227475
955025315765674
1014130524532541
1145587a379788a
1217027100aa311
137b666c6c0061
1436bcc7477b1b
15197879d23ab1
hexcda04e52f3d

14130524532541 has 2 divisors, whose sum is σ = 14130524532542. Its totient is φ = 14130524532540.

The previous prime is 14130524532529. The next prime is 14130524532601. The reversal of 14130524532541 is 14523542503141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9309491913316 + 4821032619225 = 3051146^2 + 2195685^2 .

It is a cyclic number.

It is not a de Polignac number, because 14130524532541 - 233 = 14121934597949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14130524532494 and 14130524532503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14130524539541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065262266270 + 7065262266271.

It is an arithmetic number, because the mean of its divisors is an integer number (7065262266271).

Almost surely, 214130524532541 is an apocalyptic number.

It is an amenable number.

14130524532541 is a deficient number, since it is larger than the sum of its proper divisors (1).

14130524532541 is an equidigital number, since it uses as much as digits as its factorization.

14130524532541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 40.

The spelling of 14130524532541 in words is "fourteen trillion, one hundred thirty billion, five hundred twenty-four million, five hundred thirty-two thousand, five hundred forty-one".