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1413054144373 is a prime number
BaseRepresentation
bin10100100100000000100…
…101110001111101110101
312000002100011200001001111
4110210000211301331311
5141122413330104443
63001051554155021
7204042541023004
oct24440045617565
95002304601044
101413054144373
114a5300254163
121a9a38b82a71
13a3334285461
144c56c22ac3b
1526b5420969d
hex14900971f75

1413054144373 has 2 divisors, whose sum is σ = 1413054144374. Its totient is φ = 1413054144372.

The previous prime is 1413054144367. The next prime is 1413054144377. The reversal of 1413054144373 is 3734414503141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1400241489124 + 12812655249 = 1183318^2 + 113193^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413054144373 - 29 = 1413054143861 is a prime.

It is a super-2 number, since 2×14130541443732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413054144377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706527072186 + 706527072187.

It is an arithmetic number, because the mean of its divisors is an integer number (706527072187).

Almost surely, 21413054144373 is an apocalyptic number.

It is an amenable number.

1413054144373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413054144373 is an equidigital number, since it uses as much as digits as its factorization.

1413054144373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 40.

The spelling of 1413054144373 in words is "one trillion, four hundred thirteen billion, fifty-four million, one hundred forty-four thousand, three hundred seventy-three".