14130553551138 has 24 divisors (see below), whose sum is σ = 31193863501788. Its totient is φ = 4621313110752.

The previous prime is 14130553551137. The next prime is 14130553551211. The reversal of 14130553551138 is 83115535503141.

14130553551138 is a `hidden beast` number, since 1 + 4 + 1 + 3 + 0 + 553 + 55 + 11 + 38 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 13449478026609 + 681075524529 = 3667353^2 + 825273^2 .

It is a super-3 number, since 3×14130553551138³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14130553551093 and 14130553551102.

It is not an unprimeable number, because it can be changed into a prime (14130553551137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7405949545 + ... + 7405951452.

Almost surely, 2^{14130553551138} is an apocalyptic number.

14130553551138 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

14130553551138 is an abundant number, since it is smaller than the sum of its proper divisors (17063309950650).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14130553551138 is a wasteful number, since it uses less digits than its factorization.

14130553551138 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14811901058 (or 14811901055 counting only the distinct ones).

The product of its (nonzero) digits is 540000, while the sum is 45.

The spelling of 14130553551138 in words is "fourteen trillion, one hundred thirty billion, five hundred fifty-three million, five hundred fifty-one thousand, one hundred thirty-eight".