141310442401 has 2 divisors, whose sum is σ = 141310442402. Its totient is φ = 141310442400.

The previous prime is 141310442387. The next prime is 141310442411. The reversal of 141310442401 is 104244013141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74529546001 + 66780896400 = 273001^2 + 258420^2 .

It is a cyclic number.

It is not a de Polignac number, because 141310442401 - 2⁹ = 141310441889 is a prime.

It is a super-3 number, since 3×141310442401³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (141310442411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70655221200 + 70655221201.

It is an arithmetic number, because the mean of its divisors is an integer number (70655221201).

Almost surely, 2^141310442401 is an apocalyptic number.

It is an amenable number.

141310442401 is a deficient number, since it is larger than the sum of its proper divisors (1).

141310442401 is an equidigital number, since it uses as much as digits as its factorization.

141310442401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 141310442401 its reverse (104244013141), we get a palindrome (245554455542).

The spelling of 141310442401 in words is "one hundred forty-one billion, three hundred ten million, four hundred forty-two thousand, four hundred one".