Base | Representation |
---|---|
bin | 1000001110011011000… |
… | …0100011111100100101 |
3 | 111111202011112022000021 |
4 | 2003212300203330211 |
5 | 4303400433141201 |
6 | 144530033115141 |
7 | 13131542643466 |
oct | 2034660437445 |
9 | 444664468007 |
10 | 141310443301 |
11 | 54a25074635 |
12 | 234786b8ab1 |
13 | 10430215531 |
14 | 6ba76aad6d |
15 | 3a20cc5ea1 |
hex | 20e6c23f25 |
141310443301 has 4 divisors (see below), whose sum is σ = 141311205504. Its totient is φ = 141309681100.
The previous prime is 141310443259. The next prime is 141310443341. The reversal of 141310443301 is 103344013141.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 141310443301 - 211 = 141310441253 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141310443341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96546 + ... + 540316.
It is an arithmetic number, because the mean of its divisors is an integer number (35327801376).
Almost surely, 2141310443301 is an apocalyptic number.
It is an amenable number.
141310443301 is a deficient number, since it is larger than the sum of its proper divisors (762203).
141310443301 is an equidigital number, since it uses as much as digits as its factorization.
141310443301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 762202.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 141310443301 its reverse (103344013141), we get a palindrome (244654456442).
The spelling of 141310443301 in words is "one hundred forty-one billion, three hundred ten million, four hundred forty-three thousand, three hundred one".
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