Base | Representation |
---|---|
bin | 10100100100000011111… |
… | …111110100110011101111 |
3 | 12000002111011020000111202 |
4 | 110210003333310303233 |
5 | 141123022443202112 |
6 | 3001101355240115 |
7 | 204044133615266 |
oct | 24440377646357 |
9 | 5002434200452 |
10 | 1413111303407 |
11 | 4a532a544631 |
12 | 1a9a5414903b |
13 | a334307927b |
14 | 4c575a695dd |
15 | 26b5924a6c2 |
hex | 14903ff4cef |
1413111303407 has 2 divisors, whose sum is σ = 1413111303408. Its totient is φ = 1413111303406.
The previous prime is 1413111303397. The next prime is 1413111303427. The reversal of 1413111303407 is 7043031113141.
It is a weak prime.
It is an emirp because it is prime and its reverse (7043031113141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1413111303407 - 26 = 1413111303343 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1413111303407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1413111303427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706555651703 + 706555651704.
It is an arithmetic number, because the mean of its divisors is an integer number (706555651704).
Almost surely, 21413111303407 is an apocalyptic number.
1413111303407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413111303407 is an equidigital number, since it uses as much as digits as its factorization.
1413111303407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 1413111303407 its reverse (7043031113141), we get a palindrome (8456142416548).
The spelling of 1413111303407 in words is "one trillion, four hundred thirteen billion, one hundred eleven million, three hundred three thousand, four hundred seven".
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